-4(-4v+2)-8v=2(v-4)-4

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Solution for -4(-4v+2)-8v=2(v-4)-4 equation: 



-4(-4v+2)-8v=2(v-4)-4

We move all terms to the left:

-4(-4v+2)-8v-(2(v-4)-4)=0

We add all the numbers together, and all the variables

-8v-4(-4v+2)-(2(v-4)-4)=0

We multiply parentheses

-8v+16v-(2(v-4)-4)-8=0



We calculate terms in parentheses: -(2(v-4)-4), so:

2(v-4)-4

We multiply parentheses

2v-8-4

We add all the numbers together, and all the variables

2v-12

Back to the equation:

-(2v-12)



We add all the numbers together, and all the variables

8v-(2v-12)-8=0

We get rid of parentheses

8v-2v+12-8=0

We add all the numbers together, and all the variables

6v+4=0

We move all terms containing v to the left, all other terms to the right

6v=-4

v=-4/6

v=-2/3

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