-4(-4y+6)-4y=2(y-2)-4

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Solution for -4(-4y+6)-4y=2(y-2)-4 equation:



-4(-4y+6)-4y=2(y-2)-4
We move all terms to the left:
-4(-4y+6)-4y-(2(y-2)-4)=0
We add all the numbers together, and all the variables
-4y-4(-4y+6)-(2(y-2)-4)=0
We multiply parentheses
-4y+16y-(2(y-2)-4)-24=0
We calculate terms in parentheses: -(2(y-2)-4), so:
2(y-2)-4
We multiply parentheses
2y-4-4
We add all the numbers together, and all the variables
2y-8
Back to the equation:
-(2y-8)
We add all the numbers together, and all the variables
12y-(2y-8)-24=0
We get rid of parentheses
12y-2y+8-24=0
We add all the numbers together, and all the variables
10y-16=0
We move all terms containing y to the left, all other terms to the right
10y=16
y=16/10
y=1+3/5

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