-4(-5-b)=1/3(b+27)

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Solution for -4(-5-b)=1/3(b+27) equation: 



-4(-5-b)=1/3(b+27)

We move all terms to the left:

-4(-5-b)-(1/3(b+27))=0



Domain of the equation: 3(b+27))!=0

b∈R



We add all the numbers together, and all the variables

-4(-1b-5)-(1/3(b+27))=0

We multiply parentheses

4b-(1/3(b+27))+20=0

We multiply all the terms by the denominator


4b*3(b+27))-(1+20*3(b+27))=0

Wy multiply elements

12b^2(b+60b(b=0

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