-4(-5u+3)-6u=2(u-5)-5

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Solution for -4(-5u+3)-6u=2(u-5)-5 equation: 



-4(-5u+3)-6u=2(u-5)-5

We move all terms to the left:

-4(-5u+3)-6u-(2(u-5)-5)=0

We add all the numbers together, and all the variables

-6u-4(-5u+3)-(2(u-5)-5)=0

We multiply parentheses

-6u+20u-(2(u-5)-5)-12=0



We calculate terms in parentheses: -(2(u-5)-5), so:

2(u-5)-5

We multiply parentheses

2u-10-5

We add all the numbers together, and all the variables

2u-15

Back to the equation:

-(2u-15)



We add all the numbers together, and all the variables

14u-(2u-15)-12=0

We get rid of parentheses

14u-2u+15-12=0

We add all the numbers together, and all the variables

12u+3=0

We move all terms containing u to the left, all other terms to the right

12u=-3

u=-3/12

u=-1/4

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