-4(-5y+1)-8y=6(y-2)-6

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Solution for -4(-5y+1)-8y=6(y-2)-6 equation: 



-4(-5y+1)-8y=6(y-2)-6

We move all terms to the left:

-4(-5y+1)-8y-(6(y-2)-6)=0

We add all the numbers together, and all the variables

-8y-4(-5y+1)-(6(y-2)-6)=0

We multiply parentheses

-8y+20y-(6(y-2)-6)-4=0



We calculate terms in parentheses: -(6(y-2)-6), so:

6(y-2)-6

We multiply parentheses

6y-12-6

We add all the numbers together, and all the variables

6y-18

Back to the equation:

-(6y-18)



We add all the numbers together, and all the variables

12y-(6y-18)-4=0

We get rid of parentheses

12y-6y+18-4=0

We add all the numbers together, and all the variables

6y+14=0

We move all terms containing y to the left, all other terms to the right

6y=-14

y=-14/6

y=-2+1/3

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