-4(-5y+1)=3(y-4)-8

Solution for -4(-5y+1)=3(y-4)-8 equation:

-4(-5y+1)=3(y-4)-8

We move all terms to the left:

-4(-5y+1)-(3(y-4)-8)=0

We multiply parentheses

20y-(3(y-4)-8)-4=0


We calculate terms in parentheses: -(3(y-4)-8), so:

3(y-4)-8

We multiply parentheses

3y-12-8

We add all the numbers together, and all the variables

3y-20

Back to the equation:

-(3y-20)


We get rid of parentheses

20y-3y+20-4=0

We add all the numbers together, and all the variables

17y+16=0

We move all terms containing y to the left, all other terms to the right

17y=-16

y=-16/17

y=-16/17