-4(-5y+4)-y=3(y-5)-5

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Solution for -4(-5y+4)-y=3(y-5)-5 equation:



-4(-5y+4)-y=3(y-5)-5
We move all terms to the left:
-4(-5y+4)-y-(3(y-5)-5)=0
We add all the numbers together, and all the variables
-1y-4(-5y+4)-(3(y-5)-5)=0
We multiply parentheses
-1y+20y-(3(y-5)-5)-16=0
We calculate terms in parentheses: -(3(y-5)-5), so:
3(y-5)-5
We multiply parentheses
3y-15-5
We add all the numbers together, and all the variables
3y-20
Back to the equation:
-(3y-20)
We add all the numbers together, and all the variables
19y-(3y-20)-16=0
We get rid of parentheses
19y-3y+20-16=0
We add all the numbers together, and all the variables
16y+4=0
We move all terms containing y to the left, all other terms to the right
16y=-4
y=-4/16
y=-1/4

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