-4(-6-b)=1/3(b+28)

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Solution for -4(-6-b)=1/3(b+28) equation:



-4(-6-b)=1/3(b+28)
We move all terms to the left:
-4(-6-b)-(1/3(b+28))=0
Domain of the equation: 3(b+28))!=0
b∈R
We add all the numbers together, and all the variables
-4(-1b-6)-(1/3(b+28))=0
We multiply parentheses
4b-(1/3(b+28))+24=0
We multiply all the terms by the denominator
4b*3(b+28))-(1+24*3(b+28))=0
Wy multiply elements
12b^2(b+72b(b=0

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