-4(-6x+3)-8x=2(x-7)-4

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Solution for -4(-6x+3)-8x=2(x-7)-4 equation: 



-4(-6x+3)-8x=2(x-7)-4

We move all terms to the left:

-4(-6x+3)-8x-(2(x-7)-4)=0

We add all the numbers together, and all the variables

-8x-4(-6x+3)-(2(x-7)-4)=0

We multiply parentheses

-8x+24x-(2(x-7)-4)-12=0



We calculate terms in parentheses: -(2(x-7)-4), so:

2(x-7)-4

We multiply parentheses

2x-14-4

We add all the numbers together, and all the variables

2x-18

Back to the equation:

-(2x-18)



We add all the numbers together, and all the variables

16x-(2x-18)-12=0

We get rid of parentheses

16x-2x+18-12=0

We add all the numbers together, and all the variables

14x+6=0

We move all terms containing x to the left, all other terms to the right

14x=-6

x=-6/14

x=-3/7

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