-4(-6y+1)-3y=3(y-2)-7

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Solution for -4(-6y+1)-3y=3(y-2)-7 equation: 



-4(-6y+1)-3y=3(y-2)-7

We move all terms to the left:

-4(-6y+1)-3y-(3(y-2)-7)=0

We add all the numbers together, and all the variables

-3y-4(-6y+1)-(3(y-2)-7)=0

We multiply parentheses

-3y+24y-(3(y-2)-7)-4=0



We calculate terms in parentheses: -(3(y-2)-7), so:

3(y-2)-7

We multiply parentheses

3y-6-7

We add all the numbers together, and all the variables

3y-13

Back to the equation:

-(3y-13)



We add all the numbers together, and all the variables

21y-(3y-13)-4=0

We get rid of parentheses

21y-3y+13-4=0

We add all the numbers together, and all the variables

18y+9=0

We move all terms containing y to the left, all other terms to the right

18y=-9

y=-9/18

y=-1/2

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