-4(-6y+3)-y=5(y-1)-5

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Solution for -4(-6y+3)-y=5(y-1)-5 equation: 



-4(-6y+3)-y=5(y-1)-5

We move all terms to the left:

-4(-6y+3)-y-(5(y-1)-5)=0

We add all the numbers together, and all the variables

-1y-4(-6y+3)-(5(y-1)-5)=0

We multiply parentheses

-1y+24y-(5(y-1)-5)-12=0



We calculate terms in parentheses: -(5(y-1)-5), so:

5(y-1)-5

We multiply parentheses

5y-5-5

We add all the numbers together, and all the variables

5y-10

Back to the equation:

-(5y-10)



We add all the numbers together, and all the variables

23y-(5y-10)-12=0

We get rid of parentheses

23y-5y+10-12=0

We add all the numbers together, and all the variables

18y-2=0

We move all terms containing y to the left, all other terms to the right

18y=2

y=2/18

y=1/9

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