-4(-6y+3)-y=5(y-1)-5

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Solution for -4(-6y+3)-y=5(y-1)-5 equation:



-4(-6y+3)-y=5(y-1)-5
We move all terms to the left:
-4(-6y+3)-y-(5(y-1)-5)=0
We add all the numbers together, and all the variables
-1y-4(-6y+3)-(5(y-1)-5)=0
We multiply parentheses
-1y+24y-(5(y-1)-5)-12=0
We calculate terms in parentheses: -(5(y-1)-5), so:
5(y-1)-5
We multiply parentheses
5y-5-5
We add all the numbers together, and all the variables
5y-10
Back to the equation:
-(5y-10)
We add all the numbers together, and all the variables
23y-(5y-10)-12=0
We get rid of parentheses
23y-5y+10-12=0
We add all the numbers together, and all the variables
18y-2=0
We move all terms containing y to the left, all other terms to the right
18y=2
y=2/18
y=1/9

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