-4(-7x+1)-8x=2(x-5)-8

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Solution for -4(-7x+1)-8x=2(x-5)-8 equation: 



-4(-7x+1)-8x=2(x-5)-8

We move all terms to the left:

-4(-7x+1)-8x-(2(x-5)-8)=0

We add all the numbers together, and all the variables

-8x-4(-7x+1)-(2(x-5)-8)=0

We multiply parentheses

-8x+28x-(2(x-5)-8)-4=0



We calculate terms in parentheses: -(2(x-5)-8), so:

2(x-5)-8

We multiply parentheses

2x-10-8

We add all the numbers together, and all the variables

2x-18

Back to the equation:

-(2x-18)



We add all the numbers together, and all the variables

20x-(2x-18)-4=0

We get rid of parentheses

20x-2x+18-4=0

We add all the numbers together, and all the variables

18x+14=0

We move all terms containing x to the left, all other terms to the right

18x=-14

x=-14/18

x=-7/9

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