-4(-m+2)+2m=1/2(10-10m)-3

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Solution for -4(-m+2)+2m=1/2(10-10m)-3 equation: 



-4(-m+2)+2m=1/2(10-10m)-3

We move all terms to the left:

-4(-m+2)+2m-(1/2(10-10m)-3)=0



Domain of the equation: 2(10-10m)-3)!=0

m∈R



We add all the numbers together, and all the variables

-4(-1m+2)+2m-(1/2(-10m+10)-3)=0

We add all the numbers together, and all the variables

2m-4(-1m+2)-(1/2(-10m+10)-3)=0

We multiply parentheses

2m+4m-(1/2(-10m+10)-3)-8=0

We multiply all the terms by the denominator


2m*2(-10m+10)-3)+4m*2(-10m-10m+10)-3)-(1-8*2(+10)-3)=0

We add all the numbers together, and all the variables

2m*2(-10m+10)-3)+4m*2(-20m+10)-3)-(1-8*210-3)=0

We add all the numbers together, and all the variables

-20m+2m*2(-10m+10)-3)+4m*2(=0

Wy multiply elements

4m^2(--3)-20m+4m*2(=0

We add all the numbers together, and all the variables

4m^23-20m+4m*2(=0

Wy multiply elements

4m^23+8m^2-20m=0

We do not support empression: m^23

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