-4(-m+2)2m=-1/2(10-12m)-3

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Solution for -4(-m+2)2m=-1/2(10-12m)-3 equation:



-4(-m+2)2m=-1/2(10-12m)-3
We move all terms to the left:
-4(-m+2)2m-(-1/2(10-12m)-3)=0
Domain of the equation: 2(10-12m)-3)!=0
m∈R
We add all the numbers together, and all the variables
-4(-1m+2)2m-(-1/2(-12m+10)-3)=0
We multiply parentheses
8m^2-16m-(-1/2(-12m+10)-3)=0
We multiply all the terms by the denominator
8m^2*2(-12m+10)-3)-16m*2(-12m+10)-3)-(-1=0
We add all the numbers together, and all the variables
8m^2*2(-12m+10)-12m-3)-16m*2(=0
Wy multiply elements
16m^3(--12m-3)-16m*2(=0
We do not support empression: m^3(

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