-4(-r+3)+6=2(r-2)

Solution for -4(-r+3)+6=2(r-2) equation:

Simplifying
-4(-1r + 3) + 6 = 2(r + -2)

Reorder the terms:
-4(3 + -1r) + 6 = 2(r + -2)
(3 * -4 + -1r * -4) + 6 = 2(r + -2)
(-12 + 4r) + 6 = 2(r + -2)

Reorder the terms:
-12 + 6 + 4r = 2(r + -2)

Combine like terms: -12 + 6 = -6
-6 + 4r = 2(r + -2)

Reorder the terms:
-6 + 4r = 2(-2 + r)
-6 + 4r = (-2 * 2 + r * 2)
-6 + 4r = (-4 + 2r)

Solving
-6 + 4r = -4 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-6 + 4r + -2r = -4 + 2r + -2r

Combine like terms: 4r + -2r = 2r
-6 + 2r = -4 + 2r + -2r

Combine like terms: 2r + -2r = 0
-6 + 2r = -4 + 0
-6 + 2r = -4

Add '6' to each side of the equation.
-6 + 6 + 2r = -4 + 6

Combine like terms: -6 + 6 = 0
0 + 2r = -4 + 6
2r = -4 + 6

Combine like terms: -4 + 6 = 2
2r = 2

Divide each side by '2'.
r = 1

Simplifying
r = 1