-4(-x+5/2)=5(2x-2)+1/2

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Solution for -4(-x+5/2)=5(2x-2)+1/2 equation:



-4(-x+5/2)=5(2x-2)+1/2
We move all terms to the left:
-4(-x+5/2)-(5(2x-2)+1/2)=0
We add all the numbers together, and all the variables
-4(-1x+5/2)-(5(2x-2)+1/2)=0
We multiply parentheses
4x-(5(2x-2)+1/2)-5/2*4=0
We calculate fractions
4x+(-(5(2x-2)+1*2*4)/()+()/()=0
We calculate terms in parentheses: +(-(5(2x-2)+1*2*4)/()+()/(), so:
-(5(2x-2)+1*2*4)/()+()/(
We add all the numbers together, and all the variables
-(5(2x-2)+1*2*4)/()+1
We multiply all the terms by the denominator
-(5(2x-2)+1*2*4)+1*()
We calculate terms in parentheses: -(5(2x-2)+1*2*4), so:
5(2x-2)+1*2*4
We add all the numbers together, and all the variables
5(2x-2)+8
We multiply parentheses
10x-10+8
We add all the numbers together, and all the variables
10x-2
Back to the equation:
-(10x-2)
We add all the numbers together, and all the variables
-(10x-2)
We get rid of parentheses
-10x+2
Back to the equation:
+(-10x+2)
We get rid of parentheses
4x-10x+2=0
We add all the numbers together, and all the variables
-6x+2=0
We move all terms containing x to the left, all other terms to the right
-6x=-2
x=-2/-6
x=1/3

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