-4(1+2n)-3(6n-5)=-41

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Solution for -4(1+2n)-3(6n-5)=-41 equation: 



-4(1+2n)-3(6n-5)=-41

We move all terms to the left:

-4(1+2n)-3(6n-5)-(-41)=0

We add all the numbers together, and all the variables

-4(2n+1)-3(6n-5)-(-41)=0

We add all the numbers together, and all the variables

-4(2n+1)-3(6n-5)+41=0

We multiply parentheses

-8n-18n-4+15+41=0

We add all the numbers together, and all the variables

-26n+52=0

We move all terms containing n to the left, all other terms to the right

-26n=-52

n=-52/-26

n=+2

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