If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-x/12 < 1/4
(1/6)*m-(3/4) = 1/3
(0.17*x^30)/180 = 0
(x^2-(6*x)+9)*(4-x) >= 0
(1/2)*x-(2*x)-16 = 0
| Fix-gx=h | | -x/121/4 | | 290-u=103 | | 8(x+1)+7x=-81 | | 4x+9+4x+8+4x=8x+5x+8 | | 8y+3y-4y= | | 6b^1+13b+6= | | 220=173-v | | -8x-5x+7= | | -4.2x=5 | | 4x-16x+1= | | [p-6]=5 | | 46-(2x+4)=(x+7)+x | | 2(3x-4)-7=51 | | 8x+1=3(x+4)+4 | | 80+.50x=20+.80x | | 9c-2c+yc= | | [y+4]=12 | | x^2+13x+26=-10 | | 7c-28=4c-5 | | x/_-6)=13 | | 80+.50x=20+80x | | 2x(x-4)-9=4(3-x) | | 15+36=3j | | 6+7=19x | | Y=Kx/9-1 | | 6xy-xy+7= | | T^3=3.69 | | 9h=97-16 | | -8(y+9)=24 | | 4[m+2]=36 | | 1/6m-3/4=1/3 |