-4(10c-30)+2c=2(60-10c)

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Solution for -4(10c-30)+2c=2(60-10c) equation: 



-4(10c-30)+2c=2(60-10c)

We move all terms to the left:

-4(10c-30)+2c-(2(60-10c))=0

We add all the numbers together, and all the variables

-4(10c-30)+2c-(2(-10c+60))=0

We add all the numbers together, and all the variables

2c-4(10c-30)-(2(-10c+60))=0

We multiply parentheses

2c-40c-(2(-10c+60))+120=0



We calculate terms in parentheses: -(2(-10c+60)), so:

2(-10c+60)

We multiply parentheses

-20c+120

Back to the equation:

-(-20c+120)



We add all the numbers together, and all the variables

-38c-(-20c+120)+120=0

We get rid of parentheses

-38c+20c-120+120=0

We add all the numbers together, and all the variables

-18c=0

c=0/-18

c=0

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