-4(1v+1)+6v=2(1v+2)-8

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Solution for -4(1v+1)+6v=2(1v+2)-8 equation: 



-4(1v+1)+6v=2(1v+2)-8

We move all terms to the left:

-4(1v+1)+6v-(2(1v+2)-8)=0

We add all the numbers together, and all the variables

-4(v+1)+6v-(2(v+2)-8)=0

We add all the numbers together, and all the variables

6v-4(v+1)-(2(v+2)-8)=0

We multiply parentheses

6v-4v-(2(v+2)-8)-4=0



We calculate terms in parentheses: -(2(v+2)-8), so:

2(v+2)-8

We multiply parentheses

2v+4-8

We add all the numbers together, and all the variables

2v-4

Back to the equation:

-(2v-4)



We add all the numbers together, and all the variables

2v-(2v-4)-4=0

We get rid of parentheses

2v-2v+4-4=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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