-4(1x+1)+6x=2(1x+2)-8

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Solution for -4(1x+1)+6x=2(1x+2)-8 equation:


Simplifying
-4(1x + 1) + 6x = 2(1x + 2) + -8

Reorder the terms:
-4(1 + 1x) + 6x = 2(1x + 2) + -8
(1 * -4 + 1x * -4) + 6x = 2(1x + 2) + -8
(-4 + -4x) + 6x = 2(1x + 2) + -8

Combine like terms: -4x + 6x = 2x
-4 + 2x = 2(1x + 2) + -8

Reorder the terms:
-4 + 2x = 2(2 + 1x) + -8
-4 + 2x = (2 * 2 + 1x * 2) + -8
-4 + 2x = (4 + 2x) + -8

Reorder the terms:
-4 + 2x = 4 + -8 + 2x

Combine like terms: 4 + -8 = -4
-4 + 2x = -4 + 2x

Add '4' to each side of the equation.
-4 + 4 + 2x = -4 + 4 + 2x

Combine like terms: -4 + 4 = 0
0 + 2x = -4 + 4 + 2x
2x = -4 + 4 + 2x

Combine like terms: -4 + 4 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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