-4(2+3x)+8x=40

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Solution for -4(2+3x)+8x=40 equation: 



-4(2+3x)+8x=40

We move all terms to the left:

-4(2+3x)+8x-(40)=0

We add all the numbers together, and all the variables

-4(3x+2)+8x-40=0

We add all the numbers together, and all the variables

8x-4(3x+2)-40=0

We multiply parentheses

8x-12x-8-40=0

We add all the numbers together, and all the variables

-4x-48=0

We move all terms containing x to the left, all other terms to the right

-4x=48

x=48/-4

x=-12

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