-4(2+8)=(-4x2)+(-4xN)

Solution for -4(2+8)=(-4x2)+(-4xN) equation:

-4(2+8)=(-4x^2)+(-4x)

We move all terms to the left:

-4(2+8)-((-4x^2)+(-4x))=0

We add all the numbers together, and all the variables

-((-4x^2)+(-4x))-410=0


We calculate terms in parentheses: -((-4x^2)+(-4x)), so:

(-4x^2)+(-4x)

We get rid of parentheses

-4x^2-4x

Back to the equation:

-(-4x^2-4x)


We get rid of parentheses

4x^2+4x-410=0

a = 4; b = 4; c = -410;
Δ = b2-4ac
Δ = 42-4·4·(-410)
Δ = 6576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6576}=\sqrt{16*411}=\sqrt{16}*\sqrt{411}=4\sqrt{411}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{411}}{2*4}=\frac{-4-4\sqrt{411}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{411}}{2*4}=\frac{-4+4\sqrt{411}}{8}
$