-4(2+m)+11m+4=10+7(m-2)

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Solution for -4(2+m)+11m+4=10+7(m-2) equation: 



-4(2+m)+11m+4=10+7(m-2)

We move all terms to the left:

-4(2+m)+11m+4-(10+7(m-2))=0

We add all the numbers together, and all the variables

-4(m+2)+11m-(10+7(m-2))+4=0

We add all the numbers together, and all the variables

11m-4(m+2)-(10+7(m-2))+4=0

We multiply parentheses

11m-4m-(10+7(m-2))-8+4=0



We calculate terms in parentheses: -(10+7(m-2)), so:

10+7(m-2)

determiningTheFunctionDomain
7(m-2)+10

We multiply parentheses

7m-14+10

We add all the numbers together, and all the variables

7m-4

Back to the equation:

-(7m-4)



We add all the numbers together, and all the variables

7m-(7m-4)-4=0

We get rid of parentheses

7m-7m+4-4=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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