-4(2-1y)+3=3(1y-4)

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Solution for -4(2-1y)+3=3(1y-4) equation: 



-4(2-1y)+3=3(1y-4)

We move all terms to the left:

-4(2-1y)+3-(3(1y-4))=0

We add all the numbers together, and all the variables

-4(-1y+2)-(3(y-4))+3=0

We multiply parentheses

4y-(3(y-4))-8+3=0



We calculate terms in parentheses: -(3(y-4)), so:

3(y-4)

We multiply parentheses

3y-12

Back to the equation:

-(3y-12)



We add all the numbers together, and all the variables

4y-(3y-12)-5=0

We get rid of parentheses

4y-3y+12-5=0

We add all the numbers together, and all the variables

y+7=0

We move all terms containing y to the left, all other terms to the right

y=-7

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