-4(2-3c)+2c=2c+3(c+6)

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Solution for -4(2-3c)+2c=2c+3(c+6) equation: 



-4(2-3c)+2c=2c+3(c+6)

We move all terms to the left:

-4(2-3c)+2c-(2c+3(c+6))=0

We add all the numbers together, and all the variables

-4(-3c+2)+2c-(2c+3(c+6))=0

We add all the numbers together, and all the variables

2c-4(-3c+2)-(2c+3(c+6))=0

We multiply parentheses

2c+12c-(2c+3(c+6))-8=0



We calculate terms in parentheses: -(2c+3(c+6)), so:

2c+3(c+6)

We multiply parentheses

2c+3c+18

We add all the numbers together, and all the variables

5c+18

Back to the equation:

-(5c+18)



We add all the numbers together, and all the variables

14c-(5c+18)-8=0

We get rid of parentheses

14c-5c-18-8=0

We add all the numbers together, and all the variables

9c-26=0

We move all terms containing c to the left, all other terms to the right

9c=26

c=26/9

c=2+8/9

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