-4(2-x)+8=4+2(3x+1)

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Solution for -4(2-x)+8=4+2(3x+1) equation: 



-4(2-x)+8=4+2(3x+1)

We move all terms to the left:

-4(2-x)+8-(4+2(3x+1))=0

We add all the numbers together, and all the variables

-4(-1x+2)-(4+2(3x+1))+8=0

We multiply parentheses

4x-(4+2(3x+1))-8+8=0



We calculate terms in parentheses: -(4+2(3x+1)), so:

4+2(3x+1)

determiningTheFunctionDomain
2(3x+1)+4

We multiply parentheses

6x+2+4

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We add all the numbers together, and all the variables

4x-(6x+6)=0

We get rid of parentheses

4x-6x-6=0

We add all the numbers together, and all the variables

-2x-6=0

We move all terms containing x to the left, all other terms to the right

-2x=6

x=6/-2

x=-3

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