-4(2-y)+3y-3(y-4)=12

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Solution for -4(2-y)+3y-3(y-4)=12 equation:



-4(2-y)+3y-3(y-4)=12
We move all terms to the left:
-4(2-y)+3y-3(y-4)-(12)=0
We add all the numbers together, and all the variables
-4(-1y+2)+3y-3(y-4)-12=0
We add all the numbers together, and all the variables
3y-4(-1y+2)-3(y-4)-12=0
We multiply parentheses
3y+4y-3y-8+12-12=0
We add all the numbers together, and all the variables
4y-8=0
We move all terms containing y to the left, all other terms to the right
4y=8
y=8/4
y=2

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