-4(2-y)+3y-3(y-4)=12

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Solution for -4(2-y)+3y-3(y-4)=12 equation: 



-4(2-y)+3y-3(y-4)=12

We move all terms to the left:

-4(2-y)+3y-3(y-4)-(12)=0

We add all the numbers together, and all the variables

-4(-1y+2)+3y-3(y-4)-12=0

We add all the numbers together, and all the variables

3y-4(-1y+2)-3(y-4)-12=0

We multiply parentheses

3y+4y-3y-8+12-12=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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