-4(2-y)+3y=-3(y-4)

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Solution for -4(2-y)+3y=-3(y-4) equation: 



-4(2-y)+3y=-3(y-4)

We move all terms to the left:

-4(2-y)+3y-(-3(y-4))=0

We add all the numbers together, and all the variables

-4(-1y+2)+3y-(-3(y-4))=0

We add all the numbers together, and all the variables

3y-4(-1y+2)-(-3(y-4))=0

We multiply parentheses

3y+4y-(-3(y-4))-8=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

7y-(-3y+12)-8=0

We get rid of parentheses

7y+3y-12-8=0

We add all the numbers together, and all the variables

10y-20=0

We move all terms containing y to the left, all other terms to the right

10y=20

y=20/10

y=2

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