-4(2-y)+3y=2(y-4)

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Solution for -4(2-y)+3y=2(y-4) equation: 



-4(2-y)+3y=2(y-4)

We move all terms to the left:

-4(2-y)+3y-(2(y-4))=0

We add all the numbers together, and all the variables

-4(-1y+2)+3y-(2(y-4))=0

We add all the numbers together, and all the variables

3y-4(-1y+2)-(2(y-4))=0

We multiply parentheses

3y+4y-(2(y-4))-8=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We add all the numbers together, and all the variables

7y-(2y-8)-8=0

We get rid of parentheses

7y-2y+8-8=0

We add all the numbers together, and all the variables

5y=0

y=0/5

y=0

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