-4(2-y)+3y=3(y-4

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Solution for -4(2-y)+3y=3(y-4 equation: 



-4(2-y)+3y=3(y-4

We move all terms to the left:

-4(2-y)+3y-(3(y-4)=0

We add all the numbers together, and all the variables

-4(-1y+2)+3y-(3(y-4)=0

We add all the numbers together, and all the variables

3y-4(-1y+2)-(3(y-4)=0

We multiply parentheses

3y+4y-(3(y-4)-8=0

We add all the numbers together, and all the variables

7y-(3(y-4)-8=0

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