-4(2a-2)+3a(2-a)=0

Solution for -4(2a-2)+3a(2-a)=0 equation:

-4(2a-2)+3a(2-a)=0

We add all the numbers together, and all the variables

-4(2a-2)+3a(-1a+2)=0

We multiply parentheses

-3a^2-8a+6a+8=0

We add all the numbers together, and all the variables

-3a^2-2a+8=0

a = -3; b = -2; c = +8;
Δ = b2-4ac
Δ = -22-4·(-3)·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-10}{2*-3}=\frac{-8}{-6}
=1+1/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+10}{2*-3}=\frac{12}{-6}
=-2
$