-4(2a-3)=1/2(10-2a

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Solution for -4(2a-3)=1/2(10-2a equation: 



-4(2a-3)=1/2(10-2a

We move all terms to the left:

-4(2a-3)-(1/2(10-2a)=0



Domain of the equation: 2(10-2a)!=0

a∈R



We add all the numbers together, and all the variables

-4(2a-3)-(1/2(-2a+10)=0

We multiply parentheses

-8a-(1/2(-2a+10)+12=0

We multiply all the terms by the denominator


-8a*2(-2a+10)+12-(1=0

We add all the numbers together, and all the variables

-8a*2(-2a+10)=0

Wy multiply elements

-16a^2(-=0

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