-4(2c+5)-4(2c-5)=32

Solution for -4(2c+5)-4(2c-5)=32 equation:

Simplifying
-4(2c + 5) + -4(2c + -5) = 32

Reorder the terms:
-4(5 + 2c) + -4(2c + -5) = 32
(5 * -4 + 2c * -4) + -4(2c + -5) = 32
(-20 + -8c) + -4(2c + -5) = 32

Reorder the terms:
-20 + -8c + -4(-5 + 2c) = 32
-20 + -8c + (-5 * -4 + 2c * -4) = 32
-20 + -8c + (20 + -8c) = 32

Reorder the terms:
-20 + 20 + -8c + -8c = 32

Combine like terms: -20 + 20 = 0
0 + -8c + -8c = 32
-8c + -8c = 32

Combine like terms: -8c + -8c = -16c
-16c = 32

Solving
-16c = 32

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '-16'.
c = -2

Simplifying
c = -2