-4(2m+5)=-7(1+m)-3

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Solution for -4(2m+5)=-7(1+m)-3 equation: 



-4(2m+5)=-7(1+m)-3

We move all terms to the left:

-4(2m+5)-(-7(1+m)-3)=0

We add all the numbers together, and all the variables

-4(2m+5)-(-7(m+1)-3)=0

We multiply parentheses

-8m-(-7(m+1)-3)-20=0



We calculate terms in parentheses: -(-7(m+1)-3), so:

-7(m+1)-3

We multiply parentheses

-7m-7-3

We add all the numbers together, and all the variables

-7m-10

Back to the equation:

-(-7m-10)



We get rid of parentheses

-8m+7m+10-20=0

We add all the numbers together, and all the variables

-1m-10=0

We move all terms containing m to the left, all other terms to the right

-m=10

m=10/-1

m=-10

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