-4(2n-1)-n=3(1-2n)+4

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Solution for -4(2n-1)-n=3(1-2n)+4 equation: 



-4(2n-1)-n=3(1-2n)+4

We move all terms to the left:

-4(2n-1)-n-(3(1-2n)+4)=0

We add all the numbers together, and all the variables

-4(2n-1)-n-(3(-2n+1)+4)=0

We add all the numbers together, and all the variables

-1n-4(2n-1)-(3(-2n+1)+4)=0

We multiply parentheses

-1n-8n-(3(-2n+1)+4)+4=0



We calculate terms in parentheses: -(3(-2n+1)+4), so:

3(-2n+1)+4

We multiply parentheses

-6n+3+4

We add all the numbers together, and all the variables

-6n+7

Back to the equation:

-(-6n+7)



We add all the numbers together, and all the variables

-9n-(-6n+7)+4=0

We get rid of parentheses

-9n+6n-7+4=0

We add all the numbers together, and all the variables

-3n-3=0

We move all terms containing n to the left, all other terms to the right

-3n=3

n=3/-3

n=-1

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