-4(2n-1)-n=3(1-2n)+7

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Solution for -4(2n-1)-n=3(1-2n)+7 equation:



-4(2n-1)-n=3(1-2n)+7
We move all terms to the left:
-4(2n-1)-n-(3(1-2n)+7)=0
We add all the numbers together, and all the variables
-4(2n-1)-n-(3(-2n+1)+7)=0
We add all the numbers together, and all the variables
-1n-4(2n-1)-(3(-2n+1)+7)=0
We multiply parentheses
-1n-8n-(3(-2n+1)+7)+4=0
We calculate terms in parentheses: -(3(-2n+1)+7), so:
3(-2n+1)+7
We multiply parentheses
-6n+3+7
We add all the numbers together, and all the variables
-6n+10
Back to the equation:
-(-6n+10)
We add all the numbers together, and all the variables
-9n-(-6n+10)+4=0
We get rid of parentheses
-9n+6n-10+4=0
We add all the numbers together, and all the variables
-3n-6=0
We move all terms containing n to the left, all other terms to the right
-3n=6
n=6/-3
n=-2

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