-4(2t+3)=2(5-4t)-22

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Solution for -4(2t+3)=2(5-4t)-22 equation: 


Simplifying
-4(2t + 3) = 2(5 + -4t) + -22

Reorder the terms:
-4(3 + 2t) = 2(5 + -4t) + -22
(3 * -4 + 2t * -4) = 2(5 + -4t) + -22
(-12 + -8t) = 2(5 + -4t) + -22
-12 + -8t = (5 * 2 + -4t * 2) + -22
-12 + -8t = (10 + -8t) + -22

Reorder the terms:
-12 + -8t = 10 + -22 + -8t

Combine like terms: 10 + -22 = -12
-12 + -8t = -12 + -8t

Add '12' to each side of the equation.
-12 + 12 + -8t = -12 + 12 + -8t

Combine like terms: -12 + 12 = 0
0 + -8t = -12 + 12 + -8t
-8t = -12 + 12 + -8t

Combine like terms: -12 + 12 = 0
-8t = 0 + -8t
-8t = -8t

Add '8t' to each side of the equation.
-8t + 8t = -8t + 8t

Combine like terms: -8t + 8t = 0
0 = -8t + 8t

Combine like terms: -8t + 8t = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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