-4(2u-4)+4u=4+2(3u-3)

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Solution for -4(2u-4)+4u=4+2(3u-3) equation: 



-4(2u-4)+4u=4+2(3u-3)

We move all terms to the left:

-4(2u-4)+4u-(4+2(3u-3))=0

We add all the numbers together, and all the variables

4u-4(2u-4)-(4+2(3u-3))=0

We multiply parentheses

4u-8u-(4+2(3u-3))+16=0



We calculate terms in parentheses: -(4+2(3u-3)), so:

4+2(3u-3)

determiningTheFunctionDomain
2(3u-3)+4

We multiply parentheses

6u-6+4

We add all the numbers together, and all the variables

6u-2

Back to the equation:

-(6u-2)



We add all the numbers together, and all the variables

-4u-(6u-2)+16=0

We get rid of parentheses

-4u-6u+2+16=0

We add all the numbers together, and all the variables

-10u+18=0

We move all terms containing u to the left, all other terms to the right

-10u=-18

u=-18/-10

u=1+4/5

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