-4(2u-4)+6u=8+2(3u-3)

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Solution for -4(2u-4)+6u=8+2(3u-3) equation:



-4(2u-4)+6u=8+2(3u-3)
We move all terms to the left:
-4(2u-4)+6u-(8+2(3u-3))=0
We add all the numbers together, and all the variables
6u-4(2u-4)-(8+2(3u-3))=0
We multiply parentheses
6u-8u-(8+2(3u-3))+16=0
We calculate terms in parentheses: -(8+2(3u-3)), so:
8+2(3u-3)
determiningTheFunctionDomain 2(3u-3)+8
We multiply parentheses
6u-6+8
We add all the numbers together, and all the variables
6u+2
Back to the equation:
-(6u+2)
We add all the numbers together, and all the variables
-2u-(6u+2)+16=0
We get rid of parentheses
-2u-6u-2+16=0
We add all the numbers together, and all the variables
-8u+14=0
We move all terms containing u to the left, all other terms to the right
-8u=-14
u=-14/-8
u=1+3/4

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