-4(2u-4)+6u=8+2(3u-3)

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Solution for -4(2u-4)+6u=8+2(3u-3) equation: 



-4(2u-4)+6u=8+2(3u-3)

We move all terms to the left:

-4(2u-4)+6u-(8+2(3u-3))=0

We add all the numbers together, and all the variables

6u-4(2u-4)-(8+2(3u-3))=0

We multiply parentheses

6u-8u-(8+2(3u-3))+16=0



We calculate terms in parentheses: -(8+2(3u-3)), so:

8+2(3u-3)

determiningTheFunctionDomain
2(3u-3)+8

We multiply parentheses

6u-6+8

We add all the numbers together, and all the variables

6u+2

Back to the equation:

-(6u+2)



We add all the numbers together, and all the variables

-2u-(6u+2)+16=0

We get rid of parentheses

-2u-6u-2+16=0

We add all the numbers together, and all the variables

-8u+14=0

We move all terms containing u to the left, all other terms to the right

-8u=-14

u=-14/-8

u=1+3/4

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