-4(2u-5)+3u=7(u+5)

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Solution for -4(2u-5)+3u=7(u+5) equation: 



-4(2u-5)+3u=7(u+5)

We move all terms to the left:

-4(2u-5)+3u-(7(u+5))=0

We add all the numbers together, and all the variables

3u-4(2u-5)-(7(u+5))=0

We multiply parentheses

3u-8u-(7(u+5))+20=0



We calculate terms in parentheses: -(7(u+5)), so:

7(u+5)

We multiply parentheses

7u+35

Back to the equation:

-(7u+35)



We add all the numbers together, and all the variables

-5u-(7u+35)+20=0

We get rid of parentheses

-5u-7u-35+20=0

We add all the numbers together, and all the variables

-12u-15=0

We move all terms containing u to the left, all other terms to the right

-12u=15

u=15/-12

u=-1+1/4

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