-4(2v-2)+3v=7+2(2v-7)

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Solution for -4(2v-2)+3v=7+2(2v-7) equation: 



-4(2v-2)+3v=7+2(2v-7)

We move all terms to the left:

-4(2v-2)+3v-(7+2(2v-7))=0

We add all the numbers together, and all the variables

3v-4(2v-2)-(7+2(2v-7))=0

We multiply parentheses

3v-8v-(7+2(2v-7))+8=0



We calculate terms in parentheses: -(7+2(2v-7)), so:

7+2(2v-7)

determiningTheFunctionDomain
2(2v-7)+7

We multiply parentheses

4v-14+7

We add all the numbers together, and all the variables

4v-7

Back to the equation:

-(4v-7)



We add all the numbers together, and all the variables

-5v-(4v-7)+8=0

We get rid of parentheses

-5v-4v+7+8=0

We add all the numbers together, and all the variables

-9v+15=0

We move all terms containing v to the left, all other terms to the right

-9v=-15

v=-15/-9

v=1+2/3

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