-4(2v-3)+v=2(v+3)

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Solution for -4(2v-3)+v=2(v+3) equation: 



-4(2v-3)+v=2(v+3)

We move all terms to the left:

-4(2v-3)+v-(2(v+3))=0

We add all the numbers together, and all the variables

v-4(2v-3)-(2(v+3))=0

We multiply parentheses

v-8v-(2(v+3))+12=0



We calculate terms in parentheses: -(2(v+3)), so:

2(v+3)

We multiply parentheses

2v+6

Back to the equation:

-(2v+6)



We add all the numbers together, and all the variables

-7v-(2v+6)+12=0

We get rid of parentheses

-7v-2v-6+12=0

We add all the numbers together, and all the variables

-9v+6=0

We move all terms containing v to the left, all other terms to the right

-9v=-6

v=-6/-9

v=2/3

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