-4(2v-5)+4v=6(v+4)

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Solution for -4(2v-5)+4v=6(v+4) equation: 



-4(2v-5)+4v=6(v+4)

We move all terms to the left:

-4(2v-5)+4v-(6(v+4))=0

We add all the numbers together, and all the variables

4v-4(2v-5)-(6(v+4))=0

We multiply parentheses

4v-8v-(6(v+4))+20=0



We calculate terms in parentheses: -(6(v+4)), so:

6(v+4)

We multiply parentheses

6v+24

Back to the equation:

-(6v+24)



We add all the numbers together, and all the variables

-4v-(6v+24)+20=0

We get rid of parentheses

-4v-6v-24+20=0

We add all the numbers together, and all the variables

-10v-4=0

We move all terms containing v to the left, all other terms to the right

-10v=4

v=4/-10

v=-2/5

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