-4(2v-7)+8v=6(v+6)

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Solution for -4(2v-7)+8v=6(v+6) equation: 



-4(2v-7)+8v=6(v+6)

We move all terms to the left:

-4(2v-7)+8v-(6(v+6))=0

We add all the numbers together, and all the variables

8v-4(2v-7)-(6(v+6))=0

We multiply parentheses

8v-8v-(6(v+6))+28=0



We calculate terms in parentheses: -(6(v+6)), so:

6(v+6)

We multiply parentheses

6v+36

Back to the equation:

-(6v+36)



We add all the numbers together, and all the variables

-(6v+36)+28=0

We get rid of parentheses

-6v-36+28=0

We add all the numbers together, and all the variables

-6v-8=0

We move all terms containing v to the left, all other terms to the right

-6v=8

v=8/-6

v=-1+1/3

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