-4(2x+-4)+-3(x+3)=-7(-3+x)+-10

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Solution for -4(2x+-4)+-3(x+3)=-7(-3+x)+-10 equation: 



-4(2x+-4)+-3(x+3)=-7(-3+x)+-10

We move all terms to the left:

-4(2x+-4)+-3(x+3)-(-7(-3+x)+-10)=0

We add all the numbers together, and all the variables

-4(2x-4)-3(x+3)-(-7(x-3)+-10)+=0

We add all the numbers together, and all the variables

-4(2x-4)-3(x+3)-(-7(x-3)+-10)=0

We use the square of the difference formula

-4(2x-4)-3(x+3)-(-7(x-3)-10)=0

We multiply parentheses

-8x-3x-(-7(x-3)-10)+16-9=0



We calculate terms in parentheses: -(-7(x-3)-10), so:

-7(x-3)-10

We multiply parentheses

-7x+21-10

We add all the numbers together, and all the variables

-7x+11

Back to the equation:

-(-7x+11)



We add all the numbers together, and all the variables

-11x-(-7x+11)+7=0

We get rid of parentheses

-11x+7x-11+7=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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