-4(2x+3)=-8x+-12-2(3x+1)=-6x+-2

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Solution for -4(2x+3)=-8x+-12-2(3x+1)=-6x+-2 equation: 



-4(2x+3)=-8x+-12-2(3x+1)=-6x+-2

We move all terms to the left:

-4(2x+3)-(-8x+-12-2(3x+1))=0

We use the square of the difference formula

-4(2x+3)-(-8x-12-2(3x+1))=0

We multiply parentheses

-8x-(-8x-12-2(3x+1))-12=0



We calculate terms in parentheses: -(-8x-12-2(3x+1)), so:

-8x-12-2(3x+1)

determiningTheFunctionDomain
-8x-2(3x+1)-12

We multiply parentheses

-8x-6x-2-12

We add all the numbers together, and all the variables

-14x-14

Back to the equation:

-(-14x-14)



We get rid of parentheses

-8x+14x+14-12=0

We add all the numbers together, and all the variables

6x+2=0

We move all terms containing x to the left, all other terms to the right

6x=-2

x=-2/6

x=-1/3

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