-4(2x+3)=2x+6-(8x*2)

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Solution for -4(2x+3)=2x+6-(8x*2) equation: 



-4(2x+3)=2x+6-(8x*2)

We move all terms to the left:

-4(2x+3)-(2x+6-(8x*2))=0

We add all the numbers together, and all the variables

-4(2x+3)-(2x+6-(+8x*2))=0

We multiply parentheses

-8x-(2x+6-(+8x*2))-12=0



We calculate terms in parentheses: -(2x+6-(+8x*2)), so:

2x+6-(+8x*2)

determiningTheFunctionDomain
2x-(+8x*2)+6

We get rid of parentheses

2x-8x*2+6

Wy multiply elements

2x-16x+6

We add all the numbers together, and all the variables

-14x+6

Back to the equation:

-(-14x+6)



We get rid of parentheses

-8x+14x-6-12=0

We add all the numbers together, and all the variables

6x-18=0

We move all terms containing x to the left, all other terms to the right

6x=18

x=18/6

x=3

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