-4(2x+3)=2x+6-(8x2)

Solution for -4(2x+3)=2x+6-(8x2) equation:

-4(2x+3)=2x+6-(8x^2)

We move all terms to the left:

-4(2x+3)-(2x+6-(8x^2))=0

determiningTheFunctionDomain
-(2x+6-8x^2)-4(2x+3)=0

We multiply parentheses

-(2x+6-8x^2)-8x-12=0

We get rid of parentheses

8x^2-2x-8x-6-12=0

We add all the numbers together, and all the variables

8x^2-10x-18=0

a = 8; b = -10; c = -18;
Δ = b2-4ac
Δ = -102-4·8·(-18)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*8}=\frac{-16}{16}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*8}=\frac{36}{16}
=2+1/4
$