-4(2x+3)=2x-+6-(8x+2)

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Solution for -4(2x+3)=2x-+6-(8x+2) equation:



-4(2x+3)=2x-+6-(8x+2)
We move all terms to the left:
-4(2x+3)-(2x-+6-(8x+2))=0
We use the square of the difference formula
-4(2x+3)-(2x-6-(8x+2))=0
We multiply parentheses
-8x-(2x-6-(8x+2))-12=0
We calculate terms in parentheses: -(2x-6-(8x+2)), so:
2x-6-(8x+2)
determiningTheFunctionDomain 2x-(8x+2)-6
We get rid of parentheses
2x-8x-2-6
We add all the numbers together, and all the variables
-6x-8
Back to the equation:
-(-6x-8)
We get rid of parentheses
-8x+6x+8-12=0
We add all the numbers together, and all the variables
-2x-4=0
We move all terms containing x to the left, all other terms to the right
-2x=4
x=4/-2
x=-2

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